The Latin-1 file and this html file, present standards areįollowed and the several French and Spanish words have been No changes have been made in this ascii text file. Original 1887 edition as to typography and punctuation vagaries, Original transcriber describing his care to try to duplicate the In this case however, in consideration of the note above of the Policy to reformat the text to conform to present PG Standards. Project Gutenberg Editor's Note: In reproofing and moving old PGįiles such as this to the present PG directory system it is the Indicate italics, and textual end-notes in square braces. Original exactly, including typographical and punctuationĪdditions to the text include adding the underscore character to Original Transcriber's Note: This etext is prepared directlyįrom an 1887 edition, and care has been taken to duplicate the ![]() *** START OF THIS PROJECT GUTENBERG EBOOK A STUDY IN SCARLET *** With this eBook or online at Title: A Study In Scarlet Re-use it under the terms of the Project Gutenberg License included This eBook is for the use of anyone anywhere at no cost and withĪlmost no restrictions whatsoever. The Project Gutenberg EBook of A Study In Scarlet, by Arthur Conan Doyle Self.assertEqual(len(self.getOutput().split('\n')), 90, "Testing that correct number of lines are output.") ![]() ![]() Self.assertIn("G:235", self.getOutput().replace(' ',''), "Testing that correct number of G's is output.") Self.assertIn("h:12892", self.getOutput().replace(' ',''), "Testing that correct number of h's is output.") Self.assertIn("w:4745", self.getOutput().replace(' ',''), "Testing that correct number of w's is output.") # Write a loop that prints the letters and their counts Use the same format as the original program above. To print out the occurrence counts for all of the characters. The print statements at the end of program ac10_5_5 above pick out the specific keys ‘t’ and ‘s’. The variable that refers to the dictionary goes outside the square brackets the key you're looking up goes inside. Please review the material above and then try again. letter_counts is the dictionary of counts, but you don't want to evaluate e and t as variables in order to determine which keys to look up in the dictionary.letter_counts is the dictionary of counts you want to compare the values associated with 'e' and 't'.txt is the variable that has the original text, not the dictionary of counts.Occurrences of e than t in the text of “A Study in Scarlet,” and False if t occurred more frequently? After the program runs, which of the following will print out True if there are more Watch this play out below.Ĭonsider example ac10_5_5 above. For the sake of argument, suppose it’s 25. If all is working correctly, that value should be the number of times ‘s’ has previously occurred. Then letter_counts looks up the value associated with the key ‘s’ in the dictionary letter_counts. On each iteration.) So, let’s suppose that the current character is the letter s (we are on line 11). String that txt is bound to (that’s what the for statement says to do:Įxecute lines 8-11 once for each character in txt, with the variable c bound to the current character c is a variable bound to one letter from the Letter_counts is a variable bound to a dictionary. As with all expressions, we first have to substitute values for variable names. In this case letter_counts has to beĮvaluated. Let’s break down that line in a little more detail.Īssignment statements, the right side is evaluated first. If that made perfect sense to you, skip the next two paragraphs. ![]() Here weĪre just using a variable c whose value is ‘s’ or ‘t’, or some other character. Statements referred directly to keys, with letter_counts and letter_counts. Lines 9 and 11 above may seem a little confusing at first. Print("s: " + str(letter_counts) + " occurrences") Print("t: " + str(letter_counts) + " occurrences") Letter_counts = letter_counts + 1 # increment the s counter Letter_counts = letter_counts + 1 # increment the t counter Letter_counts = 0 # initialize the s counter Letter_counts = 0 # intiialize the t counter Letter_counts = # start with an empty dictionary # now txt is one long string containing all the characters
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